What is the logarithmic form of #e^a =38.47#?

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Answer 1 · 2016-09-16T20:33:31

#a = ln(38.47)#

We have: #e^(a) = 38.47#

Let's apply #ln# to both sides of the equation:

#=> ln(e^(a)) = ln(38.47)#

Using the laws of logarithms:

#=> a ln(e) = ln(38.47)#

#=> a cdot 1 = ln(38.47)#

#=> a = ln(38.47)#