Given a solution with a pH of 2.8, what is the H^+H+ of the solution? Chemistry Acids and Bases pH calculations 1 Answer anor277 Sep 17, 2016 H^+H+ == 10^(-2.8)*mol*L^-110−2.8⋅mol⋅L−1 Explanation: pH=-log_(10)[H^+]pH=−log10[H+] Thus [H^+][H+] == 10^(-pH)*mol*L^-110−pH⋅mol⋅L−1 Answer link Related questions How do you determine ph of a solution? How do you determine pH at an equivalence point? How do you determine pH from molarity? What does alkalinity mean? What is a base? How do acid base indicators change color? What is a neutral pH? How does alkalinity affect pool water? Why is pH important in drinking water? How can I calculate the pH of a solution? See all questions in pH calculations Impact of this question 6046 views around the world You can reuse this answer Creative Commons License