Given a solution with a pH of 2.8, what is the H^+H+ of the solution?

1 Answer
Sep 17, 2016

H^+H+ == 10^(-2.8)*mol*L^-1102.8molL1

Explanation:

pH=-log_(10)[H^+]pH=log10[H+]

Thus [H^+][H+] == 10^(-pH)*mol*L^-110pHmolL1