First of all, you know that the x-intercept is 7 and the y-intercept is -6. In addition, by knowing this you can now figure out the equation of this line.
Furthermore, you now have two points you can work with (7,0 and 0,-6). To add on, as your next step you will have to find the slope of the line which you can figure out by finding the rise over the run;(y^2-y^1)/(x^2-x^1)
Therefore, your y^2 would be 0 (which comes from the point 7,0) and your y^1 would be -6 (which comes from the point 0, -6), thus when you subtract -6 from 0 you get a result of +6.
In addition, your x^2 would be 7 (which comes from the point 7,0) and your x^1 would be 0 (which come from the point 0,-6), thus when you subtract 0 from 7 you get 7.
So, now that you have the numbers 6 and 7 all you have to do is divide them so that you get the fraction 6/7. In continuation, from this you can now write the equation of the line which would be 6/7x(the slope) minus 6 (which is the y-intercept).
This is a demonstration of how the graph would look like;
graph{6/7x-6 [-7.65, 12.35, -8.15, 1.85]}
6/7x-6