How do you multiply out #8^(-2) * (16y^-4z^5)/(y^6z^-2)#?

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Answer 1 · 2016-09-19T01:34:44

#=z^7/(4y^10)#

#8^(-2) * (16y^-4z^5)/(y^6z^-2)#

#=2^(3xx(-2)).2^4.y^(-4-6).z^(5-(-2)#

#=2^-6.(2^4).y^-10.z^7#

#=2^(-6+4).y^-10.z^7#

#=2^-2.y^-10.z^7#

#=1/(2^2).(1/y^10).z^7#

#=z^7/(4y^10)#