If #e^4x-e=0# what is #x#? Alternately, if #e^(4x)-e=0# what is #x#?
2 Answers
Sep 19, 2016
Explanation:
Given
then
and (after dividing both sides by
(Using a calculator for an approximation:
Sep 19, 2016
Explanation:
#e^(4x)-e=1 " and adding e to both sides"#
#e^(4x)=e^1" and since the bases (e) are equal, then"#
#4x=1rArrx=1/4#