How do you solve #4x^{2} - 9= 17#?

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Answer 1 · 2016-09-21T02:02:35

#x=-sqrt13/sqrt2#, #sqrt 13/sqrt 2#

Solve #4x^2-9=17#

Add #9# to both sides of the equation.

#4x^2=26#

Divide both sides by #4#.

#x^2=26/4#

Simplify.

#x^2=13/2#

Take the square root of both sides.

#x=+-sqrt(13/2)#

Simplify.

#x=+-sqrt13/sqrt2#

#x=-sqrt13/sqrt2#, #sqrt 13/sqrt 2#