Question

How do you solve `x^2-5x+3=0` using the quadratic formula?

Answer 1

`x = (5 pm sqrt(13)) / (2)`

Explanation:

We have: `x^(2) - 5 x + 3 = 0`

`=> x = (- (- 5) pm sqrt((- 5)^(2) - 4 (1) (3))) / (2 (1))`

`=> x = (5 pm sqrt(25 - 12)) / (2)`

`=> x = (5 pm sqrt(13)) / (2)`

Therefore, the solutions to the equation are `x = (5 - sqrt(13)) / (2)` and `x = (5 + sqrt(13)) / (2)`.