Question

A sample of neon is collected at 2.7 atm and 12.0 degrees C. It has a volume of 2.25 L. What would be the volume of this gas at STP?

Answer 1

`"Standard temperature and pressure"` specifies `1*atm` pressure, and a temperature of `273.15*K`

Explanation:

The combined gas law holds that `(P_1V_1)/T_1=(P_2V_2)/T_2`.

And thus `V_2=(P_1xxV_1xxT_2)/(T_1xxP_2)`

`=` `(2.7*atmxx2.25*Lxx273.15*K)/(285.15*Kxx1*atm)`

`~=` `6*L`

This volume increase is reasonable as we have only marginally changed temperature, but have reduced pressure by a third.