Question

How do you solve `\frac{8}{x + 4} \geq \frac{1}{x + 4}`?

Answer 1

Solution is `x > -4`

Explanation:

It is apparent that the denominator cannot take the value `0` and hence `x+4!=0` or `x!=-4`.

If it is so, then `8/(x+4)>=1/(x+4)`

if `x+4>0` then multiplying both side by it `8/(x+4)>=1/(x+4)hArr8>=1` or `8>=1`, which is true.

if `x+4<0` then multiplying both side by it `8/(x+4)>=1/(x+4)hArr8<=1` or `8<=1`, which is false.

Hence Solution is `x+4>0` or `x > -4`