Question

What is the standard form of `y= (3x^2-x+2)^2-x`?

Answer 1

just square the expression...

Explanation:

`y=(3x^2-x+2)^2 -x`
`y= (3x^2-x+2)(3x^2-x+2)-x`
`y=3x^2(3x^2-x+2) - x(3x^2-x+2) + 2(3x^2-x+2)-x`
`y=9x^4-3x^3+6x^2 - 3x^3 +x^2 -2x +6x^2-2x+4-x`
`y=9x^4-6x^3 + 13x^2-5x+4`