How do you solve #(x+2)^2-(x-3)^2=35#?
d
d
1 Answer
Sep 25, 2016
Explanation:
#35 = (x+2)^2-(x-3)^2#
#color(white)(35) = (color(red)(cancel(color(black)(x^2)))+4x+4)-(color(red)(cancel(color(black)(x^2)))-6x+9)#
#color(white)(35) = 4x+4+6x-9#
#color(white)(35) = 10x-5#
Add
#10x = 40#
Divide both sides by
#x = 4#