What are the #x#-intercept and #y#-intercept of #y=-(2)^x+8#?

2 Answers
Sep 26, 2016

#x = 3 and y = 9#

Explanation:

At the #y# intercept, we know that #x = 0#. By substituting that into the equation we get;

#y = -2^0 + 8#
#y = 1+8#
#y=9#

At the #x# intercept, we know that #y = 0#. By substituting that into the equation we get;

#0 = -2^x + 8#
#8 = 2^x#

#x = 3#

Sep 26, 2016

#"The X-intercept is "3", and, the Y-intercept is "9#.

Explanation:

The #X#-intercept and the #Y#-intercept of a curve # C : y=f(x)# are

the #X#-co-ord. (i.e., Abscissa ) and the #Y# co-ord.

(i.e., Ordinate ) s. of the pt. of intersection of #C# with #X#-axis

(eqn., #y=0#) and #Y#-axis (eqn., #x=0#), resp.

So, to get them, we have to solve the resp. eqns.

Accordingly, for the #X#-intercept, we have to solve the eqns. :

#y=-2^x+8, and, y=0 rArr 2^x=8=2^3 rArr x=3.#

Therefore, the #X#-intercept of #C" is "3#

Similarly, the #Y#-intercept of #C" is "9.#,