10.00 ml of 0.1089 M oxalic acid neutralises 18.65 ml of sodium hydroxide solution. What is the concentration of the sodium hydroxide ?

1 Answer
Sep 26, 2016

sf([NaOH]=0.1168color(white)(x)"mol/l")

Explanation:

sf(H_2C_2O_(4(aq))+2NaOH_((aq))rarrNa_2C_2O_(4(aq))+2H_2O_((l)))

sf(n_(H_2C_2O_4)=cxxv=0.1089xx10.00/1000=0.001089)

:.sf(n_(NaOH)=0.001089xx2=0.002178)

sf(c=n/v)

:.sf([NaOH]-=(0.002178)/(0.01865)=0.1168color(white)(x)"mol/l")