Question

How do you determine the limit of `(1/(x^(2)(x+7)))` as x approaches `0`?

Answer 1

`= oo`

Explanation:

`lim_(x to 0) 1/(x^(2)(x+7))`

`= lim_(x to 0) 1/(x^2) * 1/(x+7)`

limit of product is product of limits
`= lim_(x to 0) 1/(x^2) *lim_(x to 0) 1/(x+7)`

`= lim_(x to 0) 1/(x^2) *lim_(x to 0) 1/(7)`

`= oo`