How do you simplify #(3i)(-8-2i)#?

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Answer 1 · 2016-09-29T13:46:38

#6-24i#

Starting with the original:

#(3i)(-8-2i)#

we can distribute normally:

#(3i)(-8)+(3i)(-2i)#

#(-24i)+(-6i^2)#

remember that #i=sqrt(-1)#

#(-24i)+(-6sqrt(-1)^2)#

#(-24i)+(-6(-1))#

#(-24i)+(+6)#

#6-24i#