How do you factor and simplify #3cot^2x+6cotx+3#?
1 Answer
Sep 30, 2016
Explanation:
Begin by taking out a
#color(blue)"common factor"# of 3.
#rArr3(cot^2x+2cotx+1)# inside the bracket we have a quadratic in cotx.
let
#x=cotx" then we can write"#
#3(cot^2x+2cotx+1)=3(x^2+2x+1)# and factorising
#x^2+2x+1" using the a-c method"#
#x^2+2x+1=(x+1)(x+1)=(x+1)^2# Replacing x by cotx to obtain.
#(x+1)^2=(cotx+1)^2#
#rArr3cot^2x+6cotx+3=3(cotx+1)^2#