How do you write #9x=2y+13# in slope intercept form?

2 Answers
Oct 1, 2016

Slope intercept form is #y = mx + b#.

#9x - 13 = 2y#

#y = 9/2x - 13/2#

Hopefully this helps!

Oct 1, 2016

#y=9/2x-13/2#

Explanation:

The slope-intercept form for a linear equation is #y=mx+b#, where #m# is the slope and #b# is the y-intercept.

In order to write the equation #9x=2y+13# in slope-intercept form, solve for #y#.

#9x=2y+13#

Subtract #2y# from both sides.

#-2y+9x=13#

Subtract #9x# from both sides.

#-2y=-9x+13#

Divide both sides by #-2#.

#y=(-9x)/(-2)+13/(-2)#

Simplify.

#y=9/2x-13/2#

#m=9/2#
#b=-13/2#

graph{y=9/2x-13/2 [-10.85, 9.15, -8.19, 1.81]}