How do you solve #-12< 3x - 6\leq 21#?

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Answer 1 · 2016-10-02T01:04:01

#- 2 < x leq 9#

We have: #- 12 < 3 x - 6 leq 21#

First, let's add #6# to both sides of the inequality:

#=> - 6 < 3 x leq 27#

Then, let's divide both sides by #3#:

#=> - 2 < x leq 9#

Therefore, the solution to the inequality is the interval #- 2 < x leq 9#.

Answer 2 · 2016-10-02T01:06:44

#-2 < x <= 9#

#-12 < 3x-6 <= color(white)(aa)21#

#+color(white)a6 < color(white)(aa)+6 <= +6color(white)(aaa)# Add 6 to each section

#-6/3 < (3x)/3 <= 27/3color(white)(aaa)# Divide by 3

#-2 < x <= 9#