How do you solve #96= - 6( - 4- 3y )#?

1 Answer
Nallasivam V
Oct 2, 2016

#y=4#

Explanation:

Let us have the unknown value on the left hand side

#-6(-4-3y)=96#

On the left hand side multiply all the terms inside the bracket with #-6#

#24+18y=96#

Now solve it for #y#

#18y=96-24=72#

#y=72/18=4#

#y=4#

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