How do you evaluate #2(a-b)^2-5c# given a=12, b=9, c=4? Algebra Expressions, Equations, and Functions Expressions with One or More Variables 1 Answer Shell Oct 2, 2016 The answer is #-2# Explanation: #2(color(red)a-color(blue)b)^2-5color(violet)c color(white)(aaa)# given #a=color(red)(12), b=color(blue)9, c=color(violet) 4 # Substitute #color(red)(12)# for #color(red)a#, #color(blue)9# for #color(blue)b#, and #color(violet)4# for #color(violet)c#. #2(color(red)(12)-color(blue)9)^2-5(color(violet)4)# #2(color(white)(aa)3color(white)(aaa))^2-20# #2(9)-20# #18-20# #-2# Answer link Related questions What is an example of an expression with one or more variables? How do you write expressions with one or more variables? How do you evaluate expressions when you have more than one variables? How do you evaluate the expression #3a+2b# for #a=1# and #b=-2#? How do you find the area of a triangle whose base is 2 inches and height is 4.5 inches? How do you find the volume of a sphere whose radius is 2? How do you evaluate the expression #2(x-y)# for #x=1# and #y=-2#? How do you evaluate #x^2+2x-1# when #x=2#? What is the value of #(3x+8y)/(x-2y)# if #x/(2y)=2#? How do you simplify #6-4t-4#? See all questions in Expressions with One or More Variables Impact of this question 2740 views around the world You can reuse this answer Creative Commons License