Question #2cb7b

Question

995 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-03T05:06:42

Thus, the Solns. are, #x_0, x_1#, where,

#x_0=0.20002668410486868394424635483808^c,# &,

#x_1=sqrt(pi-(x_0)^2#.

#sinx^2=1/25=0.04#

Using Calculator, we find that,

#x^2=0.0400106743539889262206207193469#.

#:. x=0.20002668410486868394424635483808^c,#

where, #^c# denotes Radian Measure.

Let us denote, by

#x_0=0.20002668410486868394424635483808^c,#

then, the other solns. in #[0,2pi]# is, #(x_1)^2=pi-(x_0)^2#.

Thus, the Solns. are, #x_0, x_1#, where,

#x_0=0.20002668410486868394424635483808^c,# &,

#x_1=sqrt(pi-(x_0)^2)#.

As Respected Zor Shekhtman has pointed out, I have missed two

more solns., which I add here, in his words :

In both cases, for #x_0 and x_1#, the corresponding negative values are solutions as well: #-x_0 and -x_1.#
.