Question

What is total IONIC concentration in a solution of `MgCl_2(aq)` at `0.25*mol*L^-1` concentration?

Answer 1

The total concentration of ions from the solute is `0.75*mol*L^-1`.

Explanation:

In aqeous solution, magnesium chloride ionizes according to the following equation:

`MgCl_2(s) rarr Mg^(2+) + 2Cl^-`

Thus three equiv of ion result for each equiv of magnesium chloride: `1xxMg^(2+) + 2xxCl^-`

So if the concentation of `MgCl_2(aq)=0.25*mol*L^-1`, then `[Mg^(2+)]=0.25*mol*L^-1`, and `[Cl^-]=0.50*mol*L^-1`.

Capisce?