Question #70242

1 Answer
Oct 4, 2016

After applying the Product Rule your answer should be

#y'= sec^3(x)+tan^2(x)sec(x)#

Explanation:

#y=uv#

You have to apply the Product Rule

#y'= uv'+u'v#

#u=sec(x)#
#u'= sec(x) tan(x)#

#v=tan(x)#
#v'=sec^2(x)#

#y'= sec(x)sec^2(x)+tan(x)sec(x)tan(x)#

Simplified

#y'= sec^3(x)+tan^2(x)sec(x)#