How do you simplify #(3y^4x^(-6)z^(-3))/( 12x^(-2)y^(-7)#?

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Answer 1 · 2016-10-05T07:38:33

#(3y^4x^(-6)z^(-3))/(12x^(-2)y^(-7))=(y^11x^(-4)z^(-3))/4#

#"given : "(3y^4x^(-6)z^(-3))/(12x^(-2)y^(-7))#

#(cancel(3)y^4cancel(x^(-6))z^(-3))/(cancel(12)cancel(x^(-2))y^(-7))=(y^((4+7)) x^(-4)z^(-3))/(4)#

#(y^11x^(-4)z^(-3))/4#

Answer 2 · 2016-10-05T07:40:15

#(3y^4x^(-6)z^(-3))/(12x^(-2)y^(-7))=(y^11x^(-4)z^(-3))/4#

#"given : "(3y^4x^(-6)z^(-3))/(12x^(-2)y^(-7))#

#(cancel(3)y^4cancel(x^(-6))z^(-3))/(cancel(12)cancel(x^(-2))y^(-7))=(y^((4+7)) x^(-4)z^(-3))/(4)#

#(y^11x^(-4)z^(-3))/4#