How would you find the slope of the line (2, 6), and (0, 2)?

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Answer 1 · 2016-10-05T14:55:59

#(y_2-y_1)/(x_2-x_1)=(2-6)/(0-2)=(-4)/-2=2=m#

#(2,6) => (x_1,y_2)#

#(0,2) => ((x_1,y_2))#

Slope formula

#(y_2-y_1)/(x_2-x_1)=(2-6)/(0-2)=(-4)/-2=2=m#

Answer 2 · 2016-10-05T15:02:33

Slope of line joining #(2,6)# and #(0,2)# is #2#

Slope of line joining #(x_1,y_1)# and #(x_2,y_2)# is

#(y_2-y_1)/(x_2-x_1)#

hence slope of line joining #(2,6)# and #(0,2)# is

#(2-6)/(0-2)=(-4)/(-2)=2#