What is the axis of symmetry and vertex for the graph # f(x) = 8 - (x+3)^2#?

1 Answer
Oct 5, 2016

The vertex is #(-3, 8)# and the axis of symmetry is #x=-3#

Explanation:

In order to find the vertex, you would have to expand the brackets, simplify all the terms and then complete the square.

Another method is instead of completing the square, a formula can be used instead: #x=b/(2a)#. This also gives the axis of symmetry.

Then we use the function to find #f(b/(2a))#, and this will give us the coordinates of the vertex.
graph{8-(x+3)^2 [-10, 10, -5, 5]}