How do you simplify #(x+6)(x-8)(x-0)#?

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Answer 1 · 2016-10-06T09:20:08

#x^3 -2x^2-48x#

If you were going to multiply three numbers together, you would multiply two first, and then multiply the answer by the third.

#8 xx 11 xx 15 = 88 xx 15 =1320#

It would not matter which 2 you choose first.

The SAME applies in algebra

#(x+6)(x-8)(x-0)#

Note that #(x-0)# is just #x#! (keep till last)

#xcolor(red)((x+6)(x-8))#

=#xcolor(red)((x^2 -8x+6x-48))#

=#x(x^2 -2x-48)" "larr# now multiply by x

=#x^3 -2x^2-48x#