How do you convert #(-sqrt6, -sqrt2)# to polar form?
1 Answer
Explanation:
You have a point expressed in cartesian coordinates
Polar coordinates find points by knowing the length of the line that connects the point to the origin, and the angle that line forms with the
The length of the line that connects
As for the angle, the formula states that
Actually, this formula works in the first quadrant. Since we are in the third one, we need to add