Question

How do you solve `-3e^(7a+9)+6=-6`?

Answer 1

`3e^(7a+9)+6==-6` does not have any solution.

Explanation:

`3e^(7a+9)+6==-6`

`hArr3e^(7a+9)==-6-6=-12` and

`e^(7a+9)==-12/3=-4`

But no power of `e` can be negative, as for all `x's`, `e^x` is positive.
graph{e^x [-10, 10, -5, 5]}

Hence, `3e^(7a+9)+6==-6` does not have any solution.