How do you find the first and second derivative of lnx^2 ? Calculus Graphing with the Second Derivative Notation for the Second Derivative 1 Answer The_tutor Oct 10, 2016 y'=2x/x^2 y''=2/x^2 Explanation: Using the chain rule we get: y'=(1/x^2)*2x=2x/x^2 y''=((x^2*2)-4x^2)/x^4=(2x^2-4x^2)/x^4=-2x^2/x^4=2/x^2 Answer link Related questions What is notation for the Second Derivative? What is Leibniz notation for the second derivative? What is the second derivative of e^(2x)? How do you find the first, second derivative for 3x^(2/3)-x^2? What is the second derivative of y=x*sqrt(16-x^2)? How do you find the first and second derivative of (lnx)/x^2? How do you find the first and second derivative of lnx^(1/2)? How do you find the first and second derivative of x(lnx)^2? How do you find the first and second derivative of ln(x^2-4)? How do you find the first and second derivative of ln(lnx^2)? See all questions in Notation for the Second Derivative Impact of this question 1849 views around the world You can reuse this answer Creative Commons License