How do you simplify #(sina+tana)/(1+cosa)#?
1 Answer
Oct 11, 2016
Explanation:
#=(tan(a)-sin(a)cos(a))/(1-cos^2(a))#
#=(tan(a)-sin(a)cos(a))/sin^2(a)#
#=(cot(a)(tan(a)-sin(a)cos(a)))/(cot(a)sin^2(a))#
#=(1-cos^2(a))/(cos(a)sin(a))#
#=sin^2(a)/(cos(a)sin(a))#
#=sin(a)/cos(a)#
#=tan(a)#