How do you solve #\sqrt { 3 x - 5 } + \sqrt { 2 x + 3 } + 1 = 0#?

1 Answer
Cesareo R.
Oct 11, 2016

No feasible solutions.

Explanation:

The existence conditions are

#3x-5ge 0->x ge 5/3# and
#2x+3ge0->x ge -3/2# so

#x ge 5/3# adopting #x = 5/3# we have

#sqrt(0)+sqrt(2 5/3+3) > 0# so the equation does not have feasible solutions

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