How do you calculate $antilog (0.6117 + -3)$ ?

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Answer 1 · 2016-10-12T15:34:25

$x=0.0040898$

Let $x=anti log(0.6117+(-3))$

then $0.6117+(-3)=logx$

or $0.6117=logx+3=log(1000x)$

and $1000x=anti log(0.6117)$

from tables, $antilog0.6117=4.0898$

and $x=0.0040898$

How do you calculate antilog (0.6117 + -3) antilog (0.6117 + -3) ?