How do you calculate $a n t i log (0.6117 + - 3)$ $antilog (0.6117 + -3)$ ?

Question

1562 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-10-12T15:34:25

$x = 0.0040898$ $x=0.0040898$

Let $x = a n t i log (0.6117 + (- 3))$ $x=anti log(0.6117+(-3))$

then $0.6117 + (- 3) = log x$ $0.6117+(-3)=logx$

or $0.6117 = log x + 3 = log (1000 x)$ $0.6117=logx+3=log(1000x)$

and $1000 x = a n t i log (0.6117)$ $1000x=anti log(0.6117)$

from tables, $a n t i log 0.6117 = 4.0898$ $antilog0.6117=4.0898$

and $x = 0.0040898$ $x=0.0040898$

How do you calculate antilog(0.6117+−3)antilog (0.6117 + -3) ?