Question

How do you solve `3^(n-2)=27`?

Answer 1

`n=5`

Explanation:

As `3^(n-2)=27`

converting it into logarithmic form, we have

`log_3 27=n-2`

But `log_3 27=log_3 3^3=3log_3 3=3xx1=3`

Hence `n-2=3`

and `n=3+2=5`