How do you solve #9\leq - 12+ 6r#?

1 Answer
Lil Del
Oct 14, 2016

The solution of the inequality is #r >= 7/2#.

Explanation:

Use inverse operations to solve for #r#, much the same as you would use inverse operations to solve an equation. The main difference is that you should strive to have the variable on the left side of the inequality symbol.

#9<= -12 + 6r#
#9 - 6r <= -12 + 6r - 6r#
#9 - 6r <= -12#
#9 - 9 - 6r <= -12 - 9#
#-6r <= -21#
#(-6r)/-6 <= (-21)/-6#

Remember that when an inequality is multiplied or divided by a negative number, the inequality symbol is flipped.

#r>= 7/2#

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