How do you solve #-\frac { 3 } { 5 } a = 2#?

1 Answer
Tony B · CW
Oct 14, 2016

#a=-10/3#

Explanation:

#-3/5a=2#

Multiply both sides #-5/3#
#=> cancel-cancel3/cancel5axx(cancel-cancel5/cancel3)=2xx(-5/3)#

#=> a=-10/3#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Added explanation about the cancelling

#(-3/5)xx(-5/3) -> (+3/3)xx(+5/5) =1xx1=1#

So for the left hand side we end up with #1xxa# which is just #a#

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