What are the coordinates of the focus of the equation of the parabola #y=1/12 x^2#?

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Answer 1 · 2016-10-14T08:18:43

The coordinate of the focus is #(0,3)#

Given -

#y=1/12x^2#

It can be written in the form

#x^2=4ay#

#1/12x^2=y#

#x^2=12y#

#x^2=4 xx 3xx y#

It is an upward facing parabola.
Focus #a=3#

The coordinate of the focus is #(0,3)#

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