How do you integrate # (x + 2)^2 / x^(1/3)#?

1 Answer
Oct 14, 2016

Expand and integrate term by term.

Explanation:

#(x+2)^2/x^(1/3) = (x^2+4x+4)/x^(1/3)#

# = x^2/x^(1/3)+(4x)/x^(1/3)+4/x^(1/3)#

# = x^(5/3)+4x^(2/3)+4x^(-1/3) #

#int (x+2)^2/x^(1/3) dx = int (x^(5/3)+4x^(2/3)+4x^(-1/3)) dx#

# = 3/8x^(8/3)+ 4* 3/5 x^(5/3) +4 (3/2)x^(2/3) +C#

Simplify as desired.