How do you solve #\sqrt { 5x - 9} - 9= 0#?

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Answer 1 · 2016-10-15T08:38:44

#x = 18#

Making #5x-9 = 9^2# we have

#9-9=0# so

#x = (9^2+9)/5=90/5=18#

Answer 2 · 2016-10-15T08:39:03

x=18

#sqrt(5x-9)-9=0#
#sqrt(5x-9)=9#
Squaring both sides
#5x-9=81#
#5x=81+9=90#
#x=90/5=18#