Question #f83fd

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Answer 1 · 2016-10-15T16:08:08

see below

#sin 2 theta=2 cot theta - (2cos^2 theta)/tan theta#

RHS:#2 cot theta - (2cos^2 theta)/tan theta=2/tan theta - 2cos^2 theta/ tan theta#

#=(2(1-cos^2 theta))/tan theta#

#=(2sin^2 theta)/tan theta#

#=(2 sin^2 theta) / (sin theta/ cos theta)#

#=2 sin^2 theta * cos theta/ sin theta#

#=2 sin theta cos theta#

#=sin 2 theta#

#=#LHS