How do you graph #3x+y=12# using intercepts?

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Answer 1 · 2016-10-17T00:10:02

Graph the x intercept #(4,0)# and the y intercept #(0,12)# and connect them with a line.

#3x+y=12#

To find the #x# intercept, set #y=0#.

#3x+0=12#

#(3x)/3=12/3#

#x=4#

The x intercept is #(4,0)#.

To find the #y# intercept, set #x=0#.

#3(0)+y=12#

#0+y=12#

#y=12#

The #x# intercept is #(0,12)#.

To graph this line using the intercepts, first graph the two points #(4,0)# and #(0,12)#. Then connect the two points with a line.

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