How do you simplify #sqrt(-13)*sqrt(-26)#?

1 Answer
MathFact-orials.blogspot.com
Oct 17, 2016

#sqrt(-1)xxsqrt13xxsqrt(-1)xxsqrt(13)xxsqrt(2)=(-1)(13)sqrt2=-13sqrt2#

Explanation:

We have:

#sqrt(-13)xxsqrt(-26)#

Let's first break this down into some smaller pieces:

#sqrt(-13)xxsqrt(-26)=sqrt(-1)xxsqrt13xxsqrt(-1)xxsqrt(13)xxsqrt(2)#

We can now multiply the #sqrt(-1)# together as well as the #sqrt(13)# to get:

#sqrt(-1)xxsqrt13xxsqrt(-1)xxsqrt(13)xxsqrt(2)=(-1)(13)sqrt2=-13sqrt2#

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