Question

How do you find the domain of `f(x)=(x+5)^(1/2)`?

Answer 1

the domain is -5 to infinity

Explanation:

`f(x)=sqrt(x+5)`
A square root is `>=0`
so `x+5>=0`
Here is a graph of the function
`x>=-5 graph{sqrt(x+5) [-10, 10, -5, 5]}`