What are the prime factors of 102?

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Answer 1 · 2016-10-20T07:40:51

Prime factors of #102# are #2xx3xx17#

It is observed that the last digit in #102# is even number, so it is divisible by #2#.

Further, sum of the digits of #102# is #3# and hence, #102# is also divisible by #3#.

Therefore, #102#

= #2xx51#

= #2xx3xx17#

Now as #17# is a prime number,

Prime factors of #102# are #2xx3xx17#