How do you solve #9y - 3( y - 3) = 27#?

1 Answer
Lil Del
Oct 21, 2016

The solution of the equation is #y = 3#.

Explanation:

Begin by distributing the #-3#. Then use inverse operations to solve the equation for #y#.

#9y - 3(y - 3) = 27#
#9y -3y + 9 = 27#
#6y + 9 = 27#
#6y +9 - 9 = 27 - 9#
#6y = 18#
#(6y)/6 = 18/6#
#y = 3#

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