Question

How do you find the vertex of `g(x)=3x^2-24x-110`?

Answer 1

THe vertex is at (4,-158)

Explanation:

`g(x)=3x^2-24x-110`
we complete the square

`g(x)=3(x^2-8x)-110`

`g(x)=3(x^2-8x+16)-110-48`

We factorise
`g(x)=3(x-4)^2-158`

So the vertex is when `x=4` `=>`y=-158#