Question

How do you write the equation `2401^(1/4)=7` in logarithmic form?

Answer 1

I tried this:

Explanation:

I would try by taking the log in base `7` of both sides:
`log_7(2401)^(1/4)=log_7(7)`
using a property of logs (exponent of the argument) and the definition of log we get:
`1/4log_7(2401)=1`
`log_7(2401)=1*4`
`log_7(2401)=4`

and so, using the definition of log we have that indeed:
`2401=7^4`