Question

How do you graph `(x-5/2)^2 + (y+4)^2 = 101/4`?

Answer 1

The equation represents a circle, center `(5/2,-4)` and radius `(sqrt101/2)`

Explanation:

The equation is
`(x-5/2)^2+(y+4)^2=101/4`

This equation looks like

`(x-a)^2+(y-b)^2=r^2`

Which is the equation of a circle, center (a,b) and radius r.

so we have a circle of center `(5/2,-4)`and radius `sqrt101/2`