What is the slope and intercept for #y+2=1/4(x-1)#?

2 Answers
Oct 27, 2016

We'll have to get this into a #y=m*x+b# form

Explanation:

Subtract #2# from both sides:
#->y+cancel2-cancel2=1/4(x-1)-2#

Now, lose the brackets:
#->y=1/4x-1/4-2#
Or:
#->y=1/4x-2 1/4#

Where #1/4# is the slope and #(0,-2 1/4)# is the #y#-intercept
graph{0.25x-2.25 [-6.83, 13.17, -6.76, 3.24]}

Oct 27, 2016

Slope: #1/4 color(white)("XXXXXX")#y-intecept: #(-2 1/4)#

Explanation:

Remember that the general slope-intercept form is
#color(white)("XXX")y=color(green)(m)x+color(blue)(b)#
with slope of #color(green)(m)# and y-intercept of #color(blue)(b)#

Given
#color(white)("XXX")y+2=1/4(x-1)#
we wish to convert this into slope-intercept form.

#color(white)("XXX")y+2 =1/4x-1/4#

#color(white)("XXX")y=color(green)(1/4)x + (color(blue)( - 2 1/4))#

So this line has a slope of #color(green)(1/4)#
and a y-intercept of #color(blue)(""(- 2 1/4))#

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