The gas inside of a container exerts 8 Pa of pressure and is at a temperature of 120 ^o K. If the temperature of the gas changes to 60 ^oC with no change in the container's volume, what is the new pressure of the gas?
1 Answer
Oct 28, 2016
Explanation:
(p1)/"T1" =(p2)/"T2"
(8)/"120" =(p2)/"60"
p2 =4 Pa